Sunday 27 November 2011

The equilibrium constant



2)      The equilibrium constant, Kc

  • An equilibrium constant can be defined in terms of concentrations for the following reaction:

aA + bB ¾ cC + dD         

 

where a = moles of A etc


  • It can be shown that:
Kc =     [C]c[D]d
                                                                        [A]a[B]            b
           
where [A] = concentration of A in mol dm-3 etc

  • Once equilibrium moles are known they need to be converted into concentrations before being put into the Kc expression. Concentration = moles/volume (in dm3)
  • If the volume is not known, use V to represent it and the V’s will almost certainly cancel
  • The units for the Kc can be determined by substituting and cancelling


Example 1 continued

Writing the KC expression for the equilibrium gives:

                        KC=       [CH3COOH][C2H5OH]
                                    [CH3COOC2H5][H2O]

Calculating equilibrium concentrations gives

Component
CH3COOC2H5
H2O
CH3COOH
C2H5OH
Initial mol
8.0
5.0
0.0
0.0
Equilibrium mol
6.0
3.0
2.0
2.0
Equilibrium conc
6.0/V
3.0/V
2.0/V
2.0/V

                        KC=       [2.0/V][2.0/V]
                                    [6.0/V][3.0/V]

                        =          4.0/18.0
                        =          0.22

                        Units = (mol dm-3)(mol dm-3)
                                    (mol dm-3)(mol dm-3)
                        =          no units (as they all cancel - this should be stated, not left blank)
                                   
Source: OCR Module 2816/01 June 2008 part question




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