2) The
equilibrium constant, Kc
- An
equilibrium constant can be defined in terms of concentrations for the
following reaction:
aA + bB ¾ cC + dD
where a = moles of A etc
- It
can be shown that:
Kc
= [C]c[D]d
[A]a[B] b
where [A] =
concentration of A in mol dm-3 etc
- Once
equilibrium moles are known they need to be converted into concentrations
before being put into the Kc expression. Concentration =
moles/volume (in dm3)
- If
the volume is not known, use V to represent it and the V’s will almost
certainly cancel
- The
units for the Kc can be determined by substituting and
cancelling
Example
1 continued
Writing the KC expression for the equilibrium gives:
KC=
[CH3COOH][C2H5OH]
[CH3COOC2H5][H2O]
Calculating equilibrium concentrations gives
Component
|
CH3COOC2H5
|
H2O
|
CH3COOH
|
C2H5OH
|
Initial mol
|
8.0
|
5.0
|
0.0
|
0.0
|
Equilibrium mol
|
6.0
|
3.0
|
2.0
|
2.0
|
Equilibrium conc
|
6.0/V
|
3.0/V
|
2.0/V
|
2.0/V
|
KC=
[2.0/V][2.0/V]
[6.0/V][3.0/V]
= 4.0/18.0
= 0.22
Units = (mol
dm-3)(mol dm-3)
(mol
dm-3)(mol dm-3)
= no units (as they all cancel - this
should be stated, not left blank)
Source: OCR Module 2816/01 June 2008 part question
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